{"id":18196,"date":"2024-02-20T03:39:42","date_gmt":"2024-02-20T03:39:42","guid":{"rendered":"https:\/\/soicau2063.minhngocxoso.com\/?p=18196"},"modified":"2024-02-20T03:39:42","modified_gmt":"2024-02-20T03:39:42","slug":"cach-tinh-tien-lo-de-mien-nam-cuc-nhanh-trong-3-phut","status":"publish","type":"post","link":"https:\/\/soicauvina.com\/cach-tinh-tien-lo-de-mien-nam-cuc-nhanh-trong-3-phut\/","title":{"rendered":"c\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 \u0111\u1ec1 mi\u1ec1n nam c\u1ef1c nhanh trong 3 ph\u00fat"},"content":{"rendered":"

\"\"<\/h4>\n

1. C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 \u0111\u1ec1 mi\u1ec1n nam theo nh\u00e0 c\u00e1i<\/h4>\n

T\u1ef7 l\u1ec7 \u0103n \u0111\u1ec1 \u0111\u1ea7u \u0111u\u00f4i c\u1ee7a nh\u00e0 c\u00e1i hi\u1ec7n nay l\u00e0 0.8 \u0103n 75, t\u1ee9c l\u00e0 n\u1ebfu ng\u01b0\u1eddi ch\u01a1i b\u1ecf ra 8.000 vn\u0111 th\u00ec s\u1ebd \u0111\u01b0\u1ee3c nh\u1eadn 75.000vn\u0111.<\/p>\n

T\u00ednh ti\u1ec1n \u0103n l\u00f4 mi\u1ec1n Nam theo nh\u00e0 c\u00e1i<\/h5>\n

C\u00e1ch t\u00ednh ti\u1ec1n \u0103n bao l\u00f4 2 \u0111\u00e0i: T\u00ednh ti\u1ec1n theo \u0111i\u1ec3m, ph\u1ed5 bi\u1ebfn nh\u1ea5t l\u00e0 1 \u0111i\u1ec3m = 16.000vn\u0111, c\u00f3 nhi\u1ec1u n\u01a1i ghi v\u1edbi gi\u00e1 14.400vn\u0111, 15.000 vn\u0111, 15.500vn\u0111. T\u1ef7 l\u1ec7 c\u01b0\u1ee3c l\u00e0 1 \u0111i\u1ec3m \u0103n 75.000vn\u0111 ho\u1eb7c 80.000vn\u0111, t\u1ee9c l\u00e0 16.000 \u0111\u1ed3ng tr\u00fang s\u1ebd \u0111\u01b0\u1ee3c 75.000 vn\u0111 ho\u1eb7c 80.000 vn\u0111, t\u00f9y t\u1eebng n\u01a1i quy \u0111\u1ecbnh.<\/p>\n

C\u00e1ch t\u00ednh ti\u1ec1n x\u1ec9u ch\u1ee7 \u0111\u1ea7u: 1 \u0111i\u1ec3m = 8.000vn\u0111, t\u1ef7 l\u1ec7 \u0103n l\u00e0 1 \u0111i\u1ec3m \u0103n 650.000 \u0111\u1ed3ng.<\/p>\n

C\u00e1ch t\u00ednh ti\u1ec1n x\u1ec9u ch\u1ee7 \u0111u\u00f4i: 1 \u0111i\u1ec3m = 8.000vn\u0111, t\u1ef7 l\u1ec7 \u0103n l\u00e0 1 \u0111i\u1ec3m \u0103n 650.000 \u0111\u1ed3ng.<\/p>\n

C\u00e1ch t\u00ednh ti\u1ec1n bao l\u00f4 3 \u0111\u00e0i (17 gi\u1ea3i): 1 \u0111i\u1ec3m = 13.600vn\u0111, t\u1ef7 l\u1ec7 \u0103n l\u00e0 1 \u0111i\u1ec3m \u0103n 650.000vn\u0111.<\/p>\n

C\u00e1ch t\u00ednh ti\u1ec1n l\u00f4 \u0111u\u00f4i 4 \u0111\u00e0i: 1 \u0111i\u1ec3m = 8.000vn\u0111, t\u1ef7 l\u1ec7 \u0103n l\u00e0 1 \u0111i\u1ec3m \u0103n 5.500.000 \u0111\u1ed3ng.<\/p>\n

C\u00e1ch t\u00ednh ti\u1ec1n \u0103n bao l\u00f4 4 \u0111\u00e0i (17 gi\u1ea3i): 1 \u0111i\u1ec3m = 12.800vn\u0111, t\u1ef7 l\u1ec7 \u0103n l\u00e0 1 \u0111i\u1ec3m \u0103n 5.500.000 \u0111\u1ed3ng.<\/p>\n

T\u00ednh ti\u1ec1n \u0103n l\u00f4 xi\u00ean theo nh\u00e0 c\u00e1i<\/h5>\n

Xi\u00ean 2 (36 gi\u1ea3i): 1 \u0111i\u1ec3m = 28.8000vn\u0111, t\u1ef7 l\u1ec7 \u0103n 1 \u0111i\u1ec3m \u0103n 650.000 \u0111\u1ed3ng.<\/p>\n

Xi\u00ean 3 (54 gi\u1ea3i): 1 \u0111i\u1ec3m = 43.200vn\u0111, t\u1ef7 l\u1ec7 \u0103n 1 \u0111i\u1ec3m \u0103n 3.500.000 \u0111\u1ed3ng.<\/p>\n

Xi\u00ean 4 (72 gi\u1ea3i): 1 \u0111i\u1ec3m = 57.600vn\u0111, t\u1ef7 l\u1ec7 \u0103n 1 \u0111i\u1ec3m \u0103n 10.000.000 \u0111\u1ed3ng.<\/p>\n

Ngo\u00e0i ra c\u00f2n c\u00f3 l\u00f4 xi\u00ean tr\u01b0\u1ee3t \u1edf m\u1ed9t s\u1ed1 n\u01a1i cho ng\u01b0\u1eddi ch\u01a1i \u0111\u00e1nh, t\u1ef7 l\u1ec7 \u0103n l\u00f4 t\u00f9y theo quy \u0111\u1ecbnh t\u1ea1i n\u01a1i \u0111\u00f3.<\/p>\n

2. To\u00e0n t\u1eadp c\u00e1ch t\u00ednh ti\u1ec1n s\u1ed1 \u0111\u1ec1 Mi\u1ec1n Nam<\/h4>\n

C\u0169ng g\u1ea7n gi\u1ed1ng v\u1edbi c\u00e1ch t\u00ednh l\u00f4 \u0111\u1ec1 Mi\u1ec1n b\u1eafc, c\u00e1ch t\u00ednh ti\u1ec1n s\u1ed1 \u0111\u1ec1 Mi\u1ec1n Nam c\u0169ng t\u01b0\u01a1ng \u0111\u1ed1i \u0111\u01a1n gi\u1ea3n. Tuy nhi\u00ean c\u00f3 nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i v\u1eabn ch\u01b0a th\u1ef1c s\u1ef1 n\u1eafm r\u00f5 \u0111\u01b0\u1ee3c s\u1ef1 ph\u00e2n bi\u1ec7t gi\u1eefa l\u00f4, \u0111\u1ec1 c\u0169ng nh\u01b0 c\u00e1ch t\u00ednh \u0111i\u1ec3m l\u00f4, t\u00ednh ti\u1ec1n c\u1ee7a n\u00f3.<\/p>\n

\"\"<\/h4>\n

C\u00e1ch t\u00ednh ti\u1ec1n \u0103n \u0110\u1ec1<\/h5>\n

\u0110\u00e1nh \u0111\u1ec1 l\u00e0 \u0111\u1eb7t c\u01b0\u1ee3c ti\u1ec1n cho 2 con s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t x\u1ed5 s\u1ed1. N\u1ebfu tr\u00fang th\u00ec t\u00ednh theo t\u1ef7 l\u1ec7 \u0103n quy \u0111\u1ecbnh v\u1edbi ch\u1ee7 \u0111\u1ec1.<\/p>\n

\u0110\u00e1nh \u0111\u1ec1 offline: Hi\u1ec7n nay v\u1edbi c\u00e1ch \u0111\u00e1nh \u0111\u1ec1 offline t\u1ee9c l\u00e0 \u0111\u00e1nh v\u1edbi c\u00e1c ch\u1ee7 \u0111\u1ec1, th\u1ea7u \u0111\u1ec1 hay c\u00f2n g\u1ecdi l\u00e0 \u201cV\u1ebd b\u00f9a\u201d quanh v\u00f9ng th\u00ec t\u1ec9 l\u1ec7 \u0103n th\u01b0\u1eddng l\u00e0 1 \u0103n 70 \u2013 1 \u0103n 75 t\u00f9y theo t\u1eebng th\u1ea7u \u0111\u1ec1 kh\u00e1c nhau. (T\u1ee9c l\u00e0 b\u1ecf ra 1 ng\u00e0n n\u1ebfu tr\u00fang th\u1eafng 70 ho\u1eb7c 75 ng\u00e0n).<\/p>\n

\u0110\u00e1nh \u0111\u1ec1 online: V\u1edbi c\u00e1ch \u0111\u00e1nh l\u00f4 \u0111\u1ec1 Mi\u1ec1n Nam online t\u1ee9c l\u00e0 tham gia c\u00e1c trang c\u00e1 c\u01b0\u1ee3c l\u00f4 \u0111\u1ec1 do c\u00e1c nh\u00e0 c\u00e1i t\u1ed5 ch\u1ee9c. C\u00e1c nh\u00e0 c\u00e1i n\u00e0y th\u01b0\u1eddng l\u00e0 c\u00e1c c\u00f4ng ty n\u01b0\u1edbc ngo\u00e0i t\u1ed5 ch\u1ee9c trang web ch\u01a1i cho ng\u01b0\u1eddi Vi\u1ec7t. C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 n\u00e0y \u0111ang ng\u00e0y c\u00e0ng ph\u1ed5 bi\u1ebfn hi\u1ec7n nay.<\/p>\n

\u0110\u1ec1 \u0111\u1ea7u: T\u1ee9c l\u00e0 \u0111\u00e1nh 2 ch\u1eef s\u1ed1 c\u1ee7a gi\u1ea3i 8. V\u1edbi lo\u1ea1i c\u01b0\u1ee3c n\u00e0y, 1 \u0111i\u1ec3m = 1.000 \u0111\u1ed3ng, t\u1ec9 l\u1ec7 \u0103n: 1 \u0103n 98.<\/p>\n

\u0110\u1ec1 \u0111u\u00f4i: T\u1ee9c l\u00e0 \u0111\u00e1nh 2 s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t. V\u1edbi lo\u1ea1i c\u01b0\u1ee3c n\u00e0y, 1 \u0111i\u1ec3m = 1.000 \u0111\u1ed3ng, t\u1ec9 l\u1ec7 \u0103n: 1 \u0103n 98.<\/p>\n

\u0110\u1ec1 \u0111\u1ea7u \u0111u\u00f4i: \u0110\u00e2y l\u00e0 lo\u1ea1i c\u01b0\u1ee3c v\u00e0o 2 ch\u1eef s\u1ed1 c\u1ee7a gi\u1ea3i 8 v\u00e0 2 s\u1ed1 cu\u1ed1i c\u1ee7a gi\u1ea3i \u0111\u1eb7c bi\u1ec7t.<\/p>\n

V\u1edbi lo\u1ea1i c\u01b0\u1ee3c n\u00e0y: 1 \u0111i\u1ec3m = 2.000 \u0111\u1ed3ng, 1 \u0111i\u1ec3m \u0103n 98. T\u1ee9c l\u00e0 c\u01b0\u1ee3c 2.000 n\u1ebfu tr\u00fang \u0103n 98.000.<\/p>\n

C\u00e1ch t\u00ednh ti\u1ec1n \u0103n L\u00f4<\/h5>\n

\u0110\u00e1nh l\u00f4 hay c\u00f2n g\u1ecdi l\u00e0 \u0111\u00e1nh bao l\u00f4 t\u1ee9c l\u00e0 b\u1ea1n \u0111\u1eb7t c\u01b0\u1ee3c v\u00e0o con s\u1ed1 2 ch\u1eef s\u1ed1 s\u1ebd ra tr\u00f9ng v\u1edbi 2 con s\u1ed1 cu\u1ed1i c\u1ee7a t\u1ea5t c\u1ea3 c\u00e1c gi\u1ea3i x\u1ed5 s\u1ed1 trong ng\u00e0y h\u00f4m \u0111\u00f3.<\/p>\n